1 条题解
-
0
C++ :
#define _GLIBCXX_IOSTREAM #include<bits/stdc++.h> typedef unsigned int uint; typedef long long ll; typedef unsigned long long ull; typedef double lf; typedef long double llf; typedef std::pair<int,int> pii; #define xx first #define yy second template<typename T> inline T max(T a,T b){return a>b?a:b;} template<typename T> inline T min(T a,T b){return a<b?a:b;} template<typename T> inline T abs(T a){return a>0?a:-a;} template<typename T> inline bool repr(T &a,T b){return a<b?a=b,1:0;} template<typename T> inline bool repl(T &a,T b){return a>b?a=b,1:0;} template<typename T> inline T gcd(T a,T b){T t;if(a<b){while(a){t=a;a=b%a;b=t;}return b;}else{while(b){t=b;b=a%b;a=t;}return a;}} template<typename T> inline T sqr(T x){return x*x;} #define mp(a,b) std::make_pair(a,b) #define pb push_back #define I inline #define mset(a,b) memset(a,b,sizeof(a)) #define mcpy(a,b) memcpy(a,b,sizeof(a)) #define fo0(i,n) for(int i=0,i##end=n;i<i##end;i++) #define fo1(i,n) for(int i=1,i##end=n;i<=i##end;i++) #define fo(i,a,b) for(int i=a,i##end=b;i<=i##end;i++) #define fd0(i,n) for(int i=(n)-1;~i;i--) #define fd1(i,n) for(int i=n;i;i--) #define fd(i,a,b) for(int i=a,i##end=b;i>=i##end;i--) #define foe(i,x)for(__typeof(x.end())i=x.begin();i!=x.end();++i) struct Cg{I char operator()(){return getchar();}}; struct Cp{I void operator()(char x){putchar(x);}}; #define OP operator #define RT return *this; #define RX x=0;char t=P();while((t<'0'||t>'9')&&t!='-')t=P();bool f=0;\ if(t=='-')t=P(),f=1;x=t-'0';for(t=P();t>='0'&&t<='9';t=P())x=x*10+t-'0' #define RL if(t=='.'){lf u=0.1;for(t=P();t>='0'&&t<='9';t=P(),u*=0.1)x+=u*(t-'0');}if(f)x=-x #define RU x=0;char t=P();while(t<'0'||t>'9')t=P();x=t-'0';for(t=P();t>='0'&&t<='9';t=P())x=x*10+t-'0' #define TR *this,x;return x; I bool IS(char x){return x==10||x==13||x==' ';}template<typename T>struct Fr{T P;I Fr&OP,(int &x) {RX;if(f)x=-x;RT}I OP int(){int x;TR}I Fr&OP,(ll &x){RX;if(f)x=-x;RT}I OP ll(){ll x;TR}I Fr&OP,(char &x) {for(x=P();IS(x);x=P());RT}I OP char(){char x;TR}I Fr&OP,(char *x){char t=P();for(;IS(t);t=P());if(~t){for(;!IS (t)&&~t;t=P())*x++=t;}*x++=0;RT}I Fr&OP,(lf &x){RX;RL;RT}I OP lf(){lf x;TR}I Fr&OP,(llf &x){RX;RL;RT}I OP llf() {llf x;TR}I Fr&OP,(uint &x){RU;RT}I OP uint(){uint x;TR}I Fr&OP,(ull &x){RU;RT}I OP ull(){ull x;TR}};Fr<Cg>in; #define WI(S) if(x){if(x<0)P('-'),x=-x;char s[S],c=0;while(x)s[c++]=x%10+'0',x/=10;while(c--)P(s[c]);}else P('0') #define WL if(y){lf t=0.5;for(int i=y;i--;)t*=0.1;if(x>=0)x+=t;else x-=t,P('-');*this,(ll)(abs(x));P('.');if(x<0)\ x=-x;while(y--){x*=10;x-=floor(x*0.1)*10;P(((int)x)%10+'0');}}else if(x>=0)*this,(ll)(x+0.5);else *this,(ll)(x-0.5); #define WU(S) if(x){char s[S],c=0;while(x)s[c++]=x%10+'0',x/=10;while(c--)P(s[c]);}else P('0') template<typename T>struct Fw{T P;I Fw&OP,(int x){WI(10);RT}I Fw&OP()(int x){WI(10);RT}I Fw&OP,(uint x){WU(10);RT} I Fw&OP()(uint x){WU(10);RT}I Fw&OP,(ll x){WI(19);RT}I Fw&OP()(ll x){WI(19);RT}I Fw&OP,(ull x){WU(20);RT}I Fw&OP() (ull x){WU(20);RT}I Fw&OP,(char x){P(x);RT}I Fw&OP()(char x){P(x);RT}I Fw&OP,(const char *x){while(*x)P(*x++);RT} I Fw&OP()(const char *x){while(*x)P(*x++);RT}I Fw&OP()(lf x,int y){WL;RT}I Fw&OP()(llf x,int y){WL;RT}};Fw<Cp>out; const int n2=512,n5=1953125; int m2[n2],m5[n5]; void exgcd(int a,int b,int&x,int&y) { if(b)exgcd(b,a%b,y,x),y-=(a/b)*x; else x=1,y=0; } inline int inv(int a,int b) { int x,y; exgcd(b,a,x,y); return y<0?y+b:y; } template<typename T>inline int pow(int a,T b,int c) { int r=1; for(;b;(b>>=1)?a=(ll)a*a%c:0) if(b&1)r=(ll)r*a%c; return r; } struct data { int x;ll y; inline void mul(const data&v,int m) { x=(ll)x*v.x%m,y+=v.y; } inline void div(const data&v,int m) { x=(ll)x*inv(v.x,m)%m,y-=v.y; } }; data g2(ll x) { data ret=(data){pow(m2[n2-1],x/n2,n2)*m2[x%n2]%n2,x/2}; if(x<2)return ret; ret.mul(g2(x/2),n2); return ret; } data g5(ll x) { data ret=(data){(int)((ll)pow(m5[n5-1],x/n5,n5)*m5[x%n5]%n5),x/5}; if(x<5)return ret; ret.mul(g5(x/5),n5); return ret; } inline int c2(ll n,ll m) { data a=g2(n); a.div(g2(m),n2); a.div(g2(n-m),n2); a.x=a.x*pow(2,a.y,n2)%n2; return a.x; } inline int c5(ll n,ll m) { data a=g5(n); a.div(g5(m),n5); a.div(g5(n-m),n5); a.x=(ll)a.x*pow(5,a.y,n5)%n5; return a.x; } inline int C(ll n,ll m) { int a=c2(n,m),b=c5(n,m); //out,n,' ',m,' ',a,' ',b,' ',(787109376ll*b+212890625ll*a)%1000000000,'\n'; return(787109376ll*b+212890625ll*a)%1000000000; } inline int d2(ll n,ll m) { data a=g2(n); a.div(g2(m),n2); a.div(g2(n-m),n2); a.x=a.x*pow(2,a.y-1,n2)%n2; return a.x; } inline int d5(ll n,ll m) { data a=g5(n); a.div(g5(m),n5); a.div(g5(n-m),n5); a.x=(ll)a.x*pow(5,a.y,n5)%n5; return (ll)a.x*(n5+1)/2%n5; } inline int D(ll n,ll m) { int a=d2(n,m),b=d5(n,m); //out,n,' ',m,' ',a,' ',b,' ',(787109376ll*b+212890625ll*a)%1000000000,'\n'; return(787109376ll*b+212890625ll*a)%1000000000; } int main() { m2[0]=1; for(int i=1;i<n2;i++) { if(i%2==0)m2[i]=m2[i-1]; else m2[i]=m2[i-1]*i%n2; } m5[0]=1; for(int i=1;i<n5;i++) { if(i%5==0)m5[i]=m5[i-1]; else m5[i]=(ll)m5[i-1]*i%n5; } int k;ll n,m; while(~scanf("%lld%lld%d",&n,&m,&k)) { int c=pow(10,k,1000000007); char s[6];sprintf(s,"%%0%dd\n",k); int ans=pow(2,n+m-1,c); //out,n,' ',m,' ',c,' ',ans,'\n'; if((n+m)%2==0) { if(m<n)(ans+=D(n+m,(n+m)/2))%=c; else(ans-=D(n+m,(n+m)/2))%=c; //out,"naive\n"; } for(ll i=(n+m-1)/2;i>m;i--) (ans+=C(n+m,i))%=c; (ans+=c)%=c; printf(s,ans); } }
- 1
信息
- ID
- 1022
- 时间
- 10000ms
- 内存
- 128MiB
- 难度
- (无)
- 标签
- (无)
- 递交数
- 0
- 已通过
- 0
- 上传者